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app server host 수정(2)

master
노승철 2 years ago
parent
commit
1091c824bf
  1. 4
      src/main/java/com/palnet/server/command/SocketCommand.java
  2. 4
      src/main/resources/application.yml

4
src/main/java/com/palnet/server/command/SocketCommand.java

@ -143,8 +143,8 @@ public class SocketCommand {
// STEP 1. Control ID 발급 -> Application Server Http 통신
try {
HttpRequest request = HttpRequest.newBuilder()
// .uri(new URI("http://127.0.0.1:8080/api/ctr/cntrl/id/" + model.getObjectId()))
.uri(new URI(
// "http://211.253.38.218:8080/api/ctr/cntrl/id/" + model.getObjectId()
env.getProperty("app.host") + "api/ctr/cntrl/id/" + model.getObjectId()
+ "/" + model.getLat()
+ "/" + model.getLng()
@ -158,7 +158,7 @@ public class SocketCommand {
.newHttpClient()
.send(request, HttpResponse.BodyHandlers.ofString());
// logger.info("CONTROL ID RESPONSE : {}", response.body());
logger.info("CONTROL ID RESPONSE : {}", response.body());
Map body = JsonUtils.fromJson(response.body(), HashMap.class);

4
src/main/resources/application.yml

@ -121,7 +121,7 @@ logging:
com.palnet: debug
app:
host: http://pav.palntour.com/
host: http://211.253.38.218:8080/
---
@ -170,4 +170,4 @@ logging:
com.palnet: debug
app:
host: http://pav.palntour.com/
host: http://211.253.38.218:8080/
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